By Syed Nasar

ISBN-10: 0070459363

ISBN-13: 9780070459366

Schaum’s strong problem-solver grants 3,000 difficulties in electrical circuits, absolutely solved step by step! The originator of the solved-problem consultant, and scholars’ favourite with over 30 million learn publications bought, Schaum’s deals a diagram-packed timesaver that will help you grasp every kind of challenge you’ll face on assessments.

difficulties disguise each region of electrical circuits, from easy devices to advanced multi-phase circuits, two-port networks, and using Laplace transforms. move on to the solutions and diagrams you wish with our special, cross-referenced index. suitable with any lecture room textual content, Schaum’s 3000 Solved difficulties in electrical Circuits is so whole it’s the best software for graduate or specialist examination prep!

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**Additional resources for 3000 Solved Problems in Electrical Circuits**

**Example text**

022% From the data, determine the voltage Vx and the current Ix' I The circuit reduction is shown in Fig. 3-28b thro~gh e. P From Fig. ::..... =2A 4+2 From Fig. 3-28d: 6 I = ---- 2 = 1 333 A From Fig. 3-28b: Ix = 3! 667 A = 13 From Fig. 0 V I 6+ 3 . ~'~;f ,3 <... E] "f +(1. (t- 1~~ Fs~ b) I 2. L1(q) Fig. n.. 86 D 35 Solve Prob. 85 without resorting to network reduction. I From Fig. 0 V Polarities of voltages across three resistors in series are shown in Fig. 3-29. points a, b, c, and d. J, /0 V 2" v 30 V e.

30. 32 Solve for the current in the 5-n resistor of the circuit shown in Fig. 4-19a. 5 A. (2.. a. n... ) (t4 Ca.... 1'\. ::. J),. 0.. ::. sa- J. n.. ) Fig. 33 In the circuit of Fig. 4-19a find the voltage across ab if the 5-n resistor is removed and the terminals ab are open-circuited. 5 V With the 5-n resistor removed from the circuit of Fig. 4-19a, the 90-V source is short-circuited. resistance that will be measured across ab. Determine the I With the voltage source short-circuited, the network reduction is shown in Fig.

6%. 6 MW. 6 MW, which is the same as previously calculated. 64 A dc generator has an open-circuit voltage of 123 V. 6 kW of power. Calculate the internal power loss within the generator. I 3 36_X _ 10_ 12= _. 1 .. - Ploss.. 65 123 1=30A='--- or A dc generator may be characterized by an ideal vol1:age source in series with a resistor. At the terminals of the generator, voltage and current measurements for two different operating conditions are V, = 115 V at 1= 10 A and V, = 105 A at 1= 15 A. Model the generator by a voltage source in series with a resistor.

### 3000 Solved Problems in Electrical Circuits by Syed Nasar

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